3.49 \(\int (1-\cos ^2(x))^{3/2} \, dx\)

Optimal. Leaf size=29 \[ -\frac {1}{3} \sin ^2(x)^{3/2} \cot (x)-\frac {2}{3} \sqrt {\sin ^2(x)} \cot (x) \]

[Out]

-1/3*cot(x)*(sin(x)^2)^(3/2)-2/3*cot(x)*(sin(x)^2)^(1/2)

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Rubi [A]  time = 0.02, antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3176, 3203, 3207, 2638} \[ -\frac {1}{3} \sin ^2(x)^{3/2} \cot (x)-\frac {2}{3} \sqrt {\sin ^2(x)} \cot (x) \]

Antiderivative was successfully verified.

[In]

Int[(1 - Cos[x]^2)^(3/2),x]

[Out]

(-2*Cot[x]*Sqrt[Sin[x]^2])/3 - (Cot[x]*(Sin[x]^2)^(3/2))/3

Rule 2638

Int[sin[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[Cos[c + d*x]/d, x] /; FreeQ[{c, d}, x]

Rule 3176

Int[(u_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2)^(p_), x_Symbol] :> Int[ActivateTrig[u*(a*cos[e + f*x]^2)^p]
, x] /; FreeQ[{a, b, e, f, p}, x] && EqQ[a + b, 0]

Rule 3203

Int[((b_.)*sin[(e_.) + (f_.)*(x_)]^2)^(p_), x_Symbol] :> -Simp[(Cot[e + f*x]*(b*Sin[e + f*x]^2)^p)/(2*f*p), x]
+ Dist[(b*(2*p - 1))/(2*p), Int[(b*Sin[e + f*x]^2)^(p - 1), x], x] /; FreeQ[{b, e, f}, x] &&  !IntegerQ[p] &&
GtQ[p, 1]

Rule 3207

Int[(u_.)*((b_.)*sin[(e_.) + (f_.)*(x_)]^(n_))^(p_), x_Symbol] :> With[{ff = FreeFactors[Sin[e + f*x], x]}, Di
st[((b*ff^n)^IntPart[p]*(b*Sin[e + f*x]^n)^FracPart[p])/(Sin[e + f*x]/ff)^(n*FracPart[p]), Int[ActivateTrig[u]
*(Sin[e + f*x]/ff)^(n*p), x], x]] /; FreeQ[{b, e, f, n, p}, x] &&  !IntegerQ[p] && IntegerQ[n] && (EqQ[u, 1] |
| MatchQ[u, ((d_.)*(trig_)[e + f*x])^(m_.) /; FreeQ[{d, m}, x] && MemberQ[{sin, cos, tan, cot, sec, csc}, trig
]])

Rubi steps

\begin {align*} \int \left (1-\cos ^2(x)\right )^{3/2} \, dx &=\int \sin ^2(x)^{3/2} \, dx\\ &=-\frac {1}{3} \cot (x) \sin ^2(x)^{3/2}+\frac {2}{3} \int \sqrt {\sin ^2(x)} \, dx\\ &=-\frac {1}{3} \cot (x) \sin ^2(x)^{3/2}+\frac {1}{3} \left (2 \csc (x) \sqrt {\sin ^2(x)}\right ) \int \sin (x) \, dx\\ &=-\frac {2}{3} \cot (x) \sqrt {\sin ^2(x)}-\frac {1}{3} \cot (x) \sin ^2(x)^{3/2}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 23, normalized size = 0.79 \[ \frac {1}{12} \sqrt {\sin ^2(x)} (\cos (3 x)-9 \cos (x)) \csc (x) \]

Antiderivative was successfully verified.

[In]

Integrate[(1 - Cos[x]^2)^(3/2),x]

[Out]

((-9*Cos[x] + Cos[3*x])*Csc[x]*Sqrt[Sin[x]^2])/12

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fricas [A]  time = 0.68, size = 11, normalized size = 0.38 \[ \frac {1}{3} \, \cos \relax (x)^{3} - \cos \relax (x) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-cos(x)^2)^(3/2),x, algorithm="fricas")

[Out]

1/3*cos(x)^3 - cos(x)

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giac [B]  time = 0.23, size = 45, normalized size = 1.55 \[ -\frac {4 \, {\left (3 \, \mathrm {sgn}\left (\tan \left (\frac {1}{2} \, x\right )^{3} + \tan \left (\frac {1}{2} \, x\right )\right ) \tan \left (\frac {1}{2} \, x\right )^{2} + \mathrm {sgn}\left (\tan \left (\frac {1}{2} \, x\right )^{3} + \tan \left (\frac {1}{2} \, x\right )\right )\right )}}{3 \, {\left (\tan \left (\frac {1}{2} \, x\right )^{2} + 1\right )}^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-cos(x)^2)^(3/2),x, algorithm="giac")

[Out]

-4/3*(3*sgn(tan(1/2*x)^3 + tan(1/2*x))*tan(1/2*x)^2 + sgn(tan(1/2*x)^3 + tan(1/2*x)))/(tan(1/2*x)^2 + 1)^3

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maple [A]  time = 1.43, size = 19, normalized size = 0.66 \[ \frac {2 \sin \relax (x ) \cos \relax (x ) \left (\cos ^{2}\relax (x )-3\right )}{3 \sqrt {2-2 \cos \left (2 x \right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-cos(x)^2)^(3/2),x)

[Out]

1/3*sin(x)*cos(x)*(cos(x)^2-3)/(sin(x)^2)^(1/2)

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maxima [A]  time = 0.98, size = 11, normalized size = 0.38 \[ -\frac {1}{12} \, \cos \left (3 \, x\right ) + \frac {3}{4} \, \cos \relax (x) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-cos(x)^2)^(3/2),x, algorithm="maxima")

[Out]

-1/12*cos(3*x) + 3/4*cos(x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.03 \[ \int {\left (1-{\cos \relax (x)}^2\right )}^{3/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - cos(x)^2)^(3/2),x)

[Out]

int((1 - cos(x)^2)^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (1 - \cos ^{2}{\relax (x )}\right )^{\frac {3}{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-cos(x)**2)**(3/2),x)

[Out]

Integral((1 - cos(x)**2)**(3/2), x)

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